A charged drop of oil of radius 2.76μm and density 920kg/m3 is held stationary in a vertically downward electric field of 1.65*106N/C.(i).Find the magnitude and sign of the charge on the drop.(ii) If the drop captures two electrons in the same electric field, what would be its acceleration? Ignore viscous drag.
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1 Answers
591(i)Magnitude shud be -ve otherwise the body can't be in equilibrium
and VÏg = qE
(ii) Now when it captures two electrons..net force on it
=(q+2e)E - VÏg
- Tanmoy Das Thank you!!!Upvote·0· Reply ·2014-04-16 09:46:43