as after redistribution of charge and writing potential difference between each cosequtive plates we get q1+(2q+q1)+(5q+q1)=0
so q1=-5q/3
therefore charge on 1st plate=5q+q1=10q/3
so charge flown=5q-10q/3=5q/3
- Akash Anand Good Work Gaurav ..keep it upUpvote·0· Reply ·2013-02-26 23:58:07