1only the parallel faces of x=L and x=2L will account for net electric flux... rest all faces will have no flux (E perpendicular to A)...
φ1 = ELL2 = a√L . L2
φ2 = E2LL2 = a√2L . L2
Net flux = φ2 - φ1 = aL5/2 (√2 - 1)
The electric field vector is given by E = a√x i . Find the flux of E thru a cube bounded by surfaces
x = l , x=2l , y = 0 , y=l , z=0 and z=l.
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