E vs x is constant.and E vs y is variable. when it is displaced perpendicular to the line line of charges
9 Answers
msp
·2009-04-22 22:00:15
Asish Mahapatra
·2009-04-22 22:11:54
GUYS: the question im editing:
for 1st bit only..
E vs x for only when particle is displaced along line joining charges
E vx y for only when particle is displaced perpendicular to line joining charges
@ani: i want field vs. x or field vs. y not potential
@iitimcomin: if i slightly displace it perpendicularly, then it will keep on going to infinity naa.. i want THAT graph
iitimcomin
·2009-04-22 22:29:07
thats more of a math question ........ bada complex equation aayegaa ........