electrostatics

Two circular rings A and B each of radius a=30cm are placed coaxially with their axes horizontal in a uniform electric field E=10^5 N/C directed vertically upwards.distance between the centres of these rings A and B is h=40 cm . ring A has a +ve charge of q1=10C hwile ring B has a -ve charge q2=20C.a particle of mass m=100g and carrying a +ve charge q=10 micro colomb is released from rest at the centre of the ring A.calculate its velocity when it has moved a distance of 40cm.(take g=10m/s2)

2 Answers

1
skygirl ·

well........ A is below B or vice-versa ?

1
Pavithra Ramamoorthy ·

same question....... a is below r above b????

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