Electrostatics

There are infinite equipotential lines all parallel to the line AB in a right angled triangular region ABC as shown.All points on the vertical line have the same potential and proportional to the length of the line.

(a)An electron kept at rest will move parallel to the vector

(i) CB (ii)BA (iii)CA (iv)will remain at rest

(b)If Ep Eq and Er denote the electric field at P,Q,R respectively then

Ep>Eq>Er (ii)Ep<Eq<Er (iii)Ep=Eq=Er (iv)none

39 Answers

1
Pavithra Ramamoorthy ·

D DIRECTION OF D FIELD AT D THREE POINTS ARE PARALLEL...........

so option (iii)Ep=Eq=Er ....

is dat d correct reason???????

1
Pavithra Ramamoorthy ·

I MEAN D LENGTH FRM DOWNWARDS(BC) IS SAME WHERE p.q.r LIE........

11
Subash ·

There is some confusion with the question (sorry if im adding more )

its been given that points on horizontal line are also equipotential

and it says points on vertical line are also equipotential :)

1
sparkle2009 ·

P Q R are not on any horizontal line,here is a better pic fr the qsn

1
Pavithra Ramamoorthy ·

@ SUBASH.... U R RIT. IN QUESTION IT HAS BEEN GIVEN DAT HORIZONTAL LINES ARE EQUIPOTENTIAL N D POINTS IN VERTICAL LINE ARE AT SAME POTENTIAL.

BOTH IMPLIES D SAME.

1
Pavithra Ramamoorthy ·

There are infinite equipotential lines all parallel to the line BC in a right angled triangular region ABC as shown..........

BUT WHERE IS D LINE BC HERE?????????????

1
sparkle2009 ·

Sorry for the confusion the question has been edited !

1
Pavithra Ramamoorthy ·

DATS FINE,.............;-)

1
Pavithra Ramamoorthy ·

U CAN SEE D DIRECTION OF D FIELD AT D THREE POINTS ARE PARALLEL...........

62
Lokesh Verma ·

phew.. so after 30 posts and a lot of discussion we are back to the original question..

so now what is the answer!

1
Pavithra Ramamoorthy ·

BUT BYAH.. THESE POINTS LIE IN DIFFERENT VERTICAL LINES BUT D POINTS ARE AT SAME POSITION IN HORIZONTAL LINE INTERSECTING THE VERTICLE LINE........

CLD U GET ME????????

1
skygirl ·

my ans for 2nd one is A..

1
°ღ•๓яυΠ·

2nd q answer is
b

1
°ღ•๓яυΠ·

and for
d first one
i m confused betwn CB and will remain at rest

bt odds in favor of CB is 3/5 :P :P

1
°ღ•๓яυΠ·

batao bhi aab rite ahi ya wrng :P

11
Subash ·

2nd answer is C

and for the reason since the equipotential surfaces are equidistant

the field is equal

11
Subash ·

for 1 the answer is CA

because A is at the highest potential

C is at the lowest potential

so electron moves parallel to CA

11
Subash ·

hey sparkle check up the answers ?

1
Honey Arora ·

for 2nd one answer shd be Ep=Eq=Er coz itz an equipotential surface

1
sparkle2009 ·

For the first question the answer is AB
For the second it is option (c)

but the source isn't too reliable which is why i had to post the question here.

11
Mani Pal Singh ·

i think .............................................

that

p,q,r are on the vertical line
why r u making unnecessry doubts???

11
Anirudh Narayanan ·

are my ans correct, sparkle??

1
sparkle2009 ·

the answers given are different,but even i got the first answer same as you

for the 2nd 1,electric field is in the -ve direction of potential gradient,isnt it?

so Ep>Eq>Er, but the answer given is Ep=Eq=Er

11
Anirudh Narayanan ·

how do u know the direction of potential gradient??

1
sparkle2009 ·

All points on the vertical line have the same potential and "proportional to the length of the line"

11
Mani Pal Singh ·

@Mr Sparkle
for the 2nd 1

E =-dV/dr

so

asit is equipotential surfaces so ΔV =0 and hence C

1
sparkle2009 ·

@Manipal singh

P,Q,R at not at same potential

Vr>Vq>Vp

1
Pavithra Ramamoorthy ·

@ sparkle .... can u explain y they r not at same potential???????

11
Mani Pal Singh ·

There are infinite equipotential lines all parallel to the line BC in a right angled triangular region ABC as shown.All points on the vertical line have the same potential and proportional to the length of the line.

do i need to say something more????

1
sparkle2009 ·

it is given ! read the question again

All points on the "vertical line" have the same potential and "proportional to the length of the line"

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