Let the tension in the string before the charge q0 was put be T and final tension be T'
Consider a small arc which subtends an angle dθ at the centre of the ring.
Writing force equations for that part and using superposition of forces we have
2T'*sin(dθ/2) = 2T*sin(dθ/2) + qo*(Rdθ*q/2ΠR)/4Πε0R2
Now, sin(dθ/2)~dθ/2
So, (T'-T)dθ = qoqdθ/8Π2εoR2
So, T'-T = increment in tension = qoq/8εoΠ2R2