EMI multi answer

A thin disc or radius R has charge Q distributed uniformly on its surface. The disc is rotated about one of its diametric axis with angular velocity w in a uniform magnetic field of magnitude B directed inward into the plane of the disc at the instant of consideration. Choose the correct alternatives

(a) The magnetic moment of the disc is QR2w/4
(b) The magnetic moment of the disc is QR2w/8
(c) Instantaneous torque acting on the disc is QR2wB/8
(d) Instantaneous torque acting on the disc is zero

6 Answers

24
eureka123 ·

M/L=q/2m
=>M=qL2m
=>M=qmR2ω4.2m=qR2ω2.4

Torque=TB=MxB=lMl lBl sinθ
SInce θ=0
=>T=0

3
iitimcomin ·

completely agree wit eure ...........

106
Asish Mahapatra ·

eure r u getting M X B as positive ... ? i was getting M and B parallel to each other. . .mayb ill hav to recheck

3
iitimcomin ·

oh!!! yes ur rite ashish ......Bis goin into the plane of the disc ... ur rite ...

106
Asish Mahapatra ·

so, inst value of torque shud be zero.... is it?

24
eureka123 ·

[3][3]
hadbadi mein galti....sorry...

editing the soln

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