Good one

A non conducting ring has linear charge density λ
match the following

a)λ=λ0 1)Electric field at the centre of the ring is in direction of -j

b)λ=λ0 cosθ ;0≤θ≤2π 2)Electric field at centre of ring is zero

c)λ=λ0 sinθ ;0≤θ≤2π 3)Electric potential at the centre is zero

d))λ=λ0 (1-cos2θ) ;0≤θ≤2π 4)Electric field at the centre of the ring is in direction of -i

4 Answers

1
vector ·

is it more than one

1
vector ·

i got
a=2
b=3,4
c=3,1
d=2 kucch bhi karke nikal diya

24
eureka123 ·

haan ans theek hai.........reason bhi bataa do.....

33
Abhishek Priyam ·

a - 2
they cancel each other.

b-3,4
Net charge in the ring is zero so potential zero at center.. (all charges are at same distance..)
I and IV quad has field in -i direction (away from them) and quad II and III has towards them -i (there is symmetry in charge direction so only -i component no j component..)

c-3,1
same reason as b

d-2
as it is proportional to sin2θ always positive so field is zero as in a (here also charge is symmetrically distributed..) But potential cannot be zero as only +ve charge..

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