Consider a solid NON-CONDUCTING sphere(of radius R) of mass M bearing charge (+)Q uniformly distributed over its volume...
at a distance a(< R) there is a spherical cavity in the sphere of radius r.
the line joining the centres of the cavity and the sphere makes an angle θ with the horizontal(positive x-axis).
a proton is kept at the centre of the cavity. Find the time in which the proton will collide with the wall of the cavity...
given data:
mass of proton = m
charge on a proton = (+)e
Discuss the case when:
(i) the non conducting sphere is kept in a gravity free zone.
(ii)the non conducting sphere is kept very near to earth's surface.(acceleration due to gravity=g)
49could not see the pic uploaded by sanchit (my weak eyes :P) so posted this one now solve
PIC::
1P.S. i think problem is ill-framed..it is not cleaar whether a is the distance to centre of cavity or not???
hmm...the electric field inside the cavity is UNIFORM =Q(a+r)/4*pi*epsilon(0)*R3[if NOT to the centre]
=Qa/4*pi*epsilon(0)*R3[if TO the centre
thanx to negative thinking induced by subhomoy bakshi in gtalk![3][3][3][3]
49arre from figure a is the distance between the centres of the 2 spheres!!!
