googly from ATGS 11

Consider a solid NON-CONDUCTING sphere(of radius R) of mass M bearing charge (+)Q uniformly distributed over its volume...

at a distance a(< R) there is a spherical cavity in the sphere of radius r.

the line joining the centres of the cavity and the sphere makes an angle θ with the horizontal(positive x-axis).

a proton is kept at the centre of the cavity. Find the time in which the proton will collide with the wall of the cavity...

given data
:
mass of proton = m
charge on a proton = (+)e

Discuss the case when:
(i) the non conducting sphere is kept in a gravity free zone.
(ii)the non conducting sphere is kept very near to earth's surface.(acceleration due to gravity=g)

7 Answers

1
sanchit ·

is this the case shubho .....

49
Subhomoy Bakshi ·

could not see the pic uploaded by sanchit (my weak eyes :P) so posted this one now solve

PIC::

66
kaymant ·

Hint:
The field inside the cavity is uniform.

49
Subhomoy Bakshi ·

:D

1
hacker ·

P.S. i think problem is ill-framed..it is not cleaar whether a is the distance to centre of cavity or not???

hmm...the electric field inside the cavity is UNIFORM =Q(a+r)/4*pi*epsilon(0)*R3[if NOT to the centre]
=Qa/4*pi*epsilon(0)*R3[if TO the centre
thanx to negative thinking induced by subhomoy bakshi in gtalk![3][3][3][3]

49
Subhomoy Bakshi ·

arre from figure a is the distance between the centres of the 2 spheres!!!

49
Subhomoy Bakshi ·

??

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