eureka plz help dude........
5 Answers
yes no
·2009-09-11 09:16:11
as the rod will move, the positive chrg will get "accumulated" on one side and negative on other(due to force by magnetic field)..find the direction using q(vXB)..positive chrg will go to B and -ve to A..chk again!!
hence,
B is at higher potential
hacker
·2009-09-11 10:22:56
ok thanx.....and what will be direction of emf.....i have no idea if we take dir. from + to - or - to +........plz tell!