1coz........ sum of d potential energy (work done) by +q charge is equal to dat of work done by -q...........
Point charges q and -q are kept at the alternate corners of a cube of side a.
Write the expression for the work done in removing all the charges far away from each other
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UP 0 DOWN 0 0 12
12 Answers
11srry.. it must be v= 8q/4pie0a
i don think any complexity involved in dis prob.. jus apply principle of super position.............. ?????????
1doin.......................... ll be bk in few min........
1by considering all pairs
[-12 + 6(2)^0.5 - 4/(3)^0.5 ]{q^2}*(9*10^9)
62my no body..
I think you have made a small mistake with the sign..
it is -ve of the whole thing.. and the side is not there!
3LET IT BE ALL EMPTY ........
NOW +q is brought .........U=0
now in presence of +q ...-q is kept at dist. a
work done =-kq^2/a
now another +q is put
W = kq^2/√2 a - kq2/a
then -q ....BLAH BLAH FINALLY NET WORK DONE IN BRINGING ALL OF THEM TOGETHER
Wnet = 12 kq2/√2a - 12kq2/a - 4kq2/√5a
1we have to consider and calculate the total potential energy of the system !!