please give me some hints on how to solve this q...
In a LRC circuit, R=20 Ohm , pot diff across cap = 100 V and irms=11 A. An AC source is connected(220V,50HZ) . Calculate pot diff across inductor.
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2 Answers
Asish Mahapatra
·2009-09-09 01:23:51
is it LRC series or parallel?
If it is series,
Then Z = √R2+(XL-XC)2 = Vrms/irms .. (i)
So, pd across cap = i.XC .... (ii)
Solving (i) and (ii) ull get the values of C and L. So now u can calculate pd across inductor to be as below
pd across inductor = i.XL
i=irms
cipher1729
·2009-09-09 04:49:18
it is series
100= 11 X xc
100/11= xc
from eqn 1 we get that xl=xc ,
so,
i X xl=100
but answer is given as 200