ilower=2
1upper=4
B=10-7i*(cosθ1+casθ2)/d
As magnetic field by each wire is just diff. in direction and proportional to i.The magnetic field by lower(reflection) is cancelled,and net current can be assumed as 2 in upper and 0 in lower.
B net=3*(10-7*2*(1/2+1/2)/√3)=2√3*10-7
B0=2
2 Answers
Swaraj Dalmia
·2012-03-23 05:03:23