S= V/I - G
here S is d resistnce of d shunt and G is d resistnce of d galvanometr
d scale of a galvanometer requires of resistance 50Ω
contins 25 divisions .on passing a current of 1 division .d resistance dat must b added to it so dat it may become a voltmeter of range 2.5V[ans-200Ω]
d resistance of galvanometer is of 18000Ω it range is 200 volts .a bulb of resistance 2000Ω is connected by mistake dis is connected in series with d bulb wat reading does it indicate[ans-180]
S= V/I - G
here S is d resistnce of d shunt and G is d resistnce of d galvanometr