not gettig ans...

two point charges q1 and q2 are fixed & placed distance s apart.Now slab(dielectric) of thickness t and relative permittivity E is inserted. Find force of b/w q1 and q2

16 Answers

1
RAY ·

force is unchanged due to surface beetwen two charges :)

1
RAY ·

i think u r askin from Briliants full test right eure??

11
Devil ·

Permitivity is different, so force should change.

1
RAY ·

but it is immaterial of any surfaces in between...there r so many surfaces betwwen earth n sun but force is always the same

1
RAY ·

it is like gravitational force........yaar i have also done a question...like dis.....

11
Devil ·

No - there the permitivity of vaccum is considered, which is const.

Here E is the permitivity - which is different from that of air.

1
RAY ·

uum...yaar capacitence changes but force doesnt change :)

11
Tush Watts ·

Yup, Soumik is right,

Force b/w two point charges is given by F = k q1 q2r 2
where k = 1 / (4∩ E0 Er)
where E0 is the absolute permittivity of the free space, and Er is the relative permittivity of medium, which is also knon as dielectric const.

Er for vacuum is one, for all other mediums it is greater than one and for conductors, it is infinite.

1
RAY ·

hmmmmmm.........dunno...wait lemme check

1
RAY ·

is permitivity and dielectric constant same??

11
Tush Watts ·

Relative Permittivity is same as Dielectric const.

1
RAY ·

uum ok..den i might be wrong

24
eureka123 ·

[3]
u all too making same mistake.....

ths is not the ans

24
eureka123 ·

anyone got ans???

11
swaraj jena ·

i think this will b the answer
let two charges are at a distance s apart in air so force b/w them =kq1q2/s2

now these two charges are at a distance x in any medium with relative permitivity m
now force between them =kq1q2/x2m
let these force b equal so we will find tht x2m=s2=>x=s/√m
from this expression we found tht x distance in water will b equ√al to s/√m distance in air to hav same force b/w two charge
hence for ur question as thickness z given t so it will b equivalent to t√E
now total distance ll b t√E+s-t
now puting it in the formula and i found F=kq1q2/(t√E-t+s)2
iz it correct

24
eureka123 ·

i think u r right....[1]

thx everyone

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