106Hint: conductors are equipotential.
=> VA = VB
Also V at A due to induced charges = 0
Now VB = Vat B due to Q + Vdue to induced
Similarly VA = Vat A due to Q + Vdue to induced (=0)
Ans: kQ(1/r - 1/r')
A charge Q is placed at a distance of r from the center of a neutral solid spherical conductor as shown. Find the potential at B due to induced charges present on surface of solid sphere [A is centre of the sphere]
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106