two identical parallel plate capacitors are connected in parallel to a 3V battery.the battery is disconnected and the two capacitors are joined in series.what is potentiasl diference across combination?
1hmm.mera purana dbt hai ye mera answer 6V ayya tha..book wrote 12V .......lets wait for others!
1ok so this is how i did it.
when capac. are connected to battery, current will flow until volatge at all points is 3V. so voltage across 2 parallel capacitors has to be 3V.
now, V=Q/C, since they are in parallel, it will be, 3=Q/2C, so Q=6C
now, connect them in series.
V=Q/C = Q/C/2 = 2(Q/C)=2(6C/C) = 12
1@madhumitha supossedly i m not tlking but just posting a reply!
when connected in series it will be a equivalent capacitor with charge 3C and equivalent capacitor of C/2
therefore V=6V[1]
u made a blunder in ur solution
1umm yeah ur right. my bad. idk then, answer shuold be 6