Heat = I2RT
T = dt
I2 = I02e-2T/RC.
I02 = E2/R2
H= 0∫RCE2e-2T/RC dt/R2
Solve it further to get the answer
Intergration is simple . Let x = T/RC And the integration will be soloved
a capacitor C is charged through a resistance R by a batt of emf E by closin switch at t=0.find amt of heat energy dissipaed in d resistor R durin d 1st tym constant??
Heat = I2RT
T = dt
I2 = I02e-2T/RC.
I02 = E2/R2
H= 0∫RCE2e-2T/RC dt/R2
Solve it further to get the answer
Intergration is simple . Let x = T/RC And the integration will be soloved