resistances&potentiometer.......

1.AJ=40cm.when R1&R2 are interchanged ,AJ'=30cm.thenAB=
a.70cm b.75cm c.100cm d.125cm
2.the potential at A is 3 times the e.m.f of 1 of the cells.the ratio of the two emfs a.2:1 b.3:1 c.4:1 d.5:1
3.find eq.resistance btwn A&B. a.0.6 b.0.4 c.0.8 d.0.1

4 Answers

1
°ღ•๓яυΠ·

1st

let AB=x
so
R1/R2 =AJ/BJ

R1/R2=40/x-40

nw afta interchnging

R2/R1=AJ'/BJ`

R2/R1=30/x-30

solving u get xas 70

1
°ღ•๓яυΠ·

3rd sum m gettin equivalnt resitnce as 4

bt ur diagrm atleast d middle one is nt clear itz 8 or 6 ??
d one originating frm A n then terminating at d junction of 4 and 3.5

1
°ღ•๓яυΠ·

i assumed to b 6

24
eureka123 ·

2)
let RHS battery=E1 and LHS battery =E2
and E1>E2 and VA=3E2

Req=6 =>I=E1-E2/6

apply loop eqn.
E1-3I=VA

put the values of I and VA to get E1:E2=5:1

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