1actually.R4 will not be shorted as the p.d. across R4 is 25/2 V and by calculation it is coming Req=8
Hey friends plz help me in this.......
I want to clear my concept........
What will be the Eq. resistance b/w the points A and B....
Each resistance in the circuit is equal to 5 Ω
According to CBSE syllabus...... Req = 8 Ω
But the thing which I 've read is that the resistor R4 will get short circuited because the points F and G being equipotential points.......
Which concept is correct.......
By solving this i am getting Req = 25/3 Ω
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3 Answers
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1Actually u got wrong somewhere else.
Potential at F is due to current through R5 as well as the partial current through R4.[Current get divided at G. One part goes through R4 and other through R3.]
So u can't put in the idea of short circuit in the problem.
1exactly...R4 will not get short-circuited..how can they be at same potential?? they need to remain at equivalent points as seen from either way to remain at same potential....
