sir i am in 11th....can u explain a bit more plzz....
Consider three charges q,q and -q is placed at the vertices of an equilateral triangle, as shown in fig what is the force on each charge?
\left|F_{1} \right|=\left|F_{2} \right|=F and \left|F_{3} \right|=\sqrt{3}F
-
UP 0 DOWN 0 0 4
4 Answers
adarsha what is the doubt here?
Have you studied vectors? If you are in xi then fine..
otehrwise you need to buck up and do really well from here on..
See the question you have to find the force in vector form and add...
firstly
the force between any 2 charge sis governed by couloumb`s law
now 2nd ly
any charge is applying a force on the other charge
so for any one given charge the forces on it due to other 2 charges differ by an angle of 60
so now use vector law f addition to find the resultant forces
hey understand carefully.... here the angle made by the two coulombic force vectors for a given charge let at A is 120°.so resultant is equal to the force by one charge i.e., kq2/a2 where a is the side of triangle abc. now net force on charge at A is equals to (kq2/a2+F1) ...F1 IS THE FORCE GIVEN ON CHARGE AT A........ SIMILARLY FOR CHARGE AT B.
BUT TAKE ANGLE BETWEEN VECTORS F31 AND F32 =60°