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IIT JEE 2015 Answers › Electricity and magnetism questions › Solve

Three balls of radii 'R' are placed at the corners of an equilateral triangle of side 4R. Ball 1 is given charge +Q and balls two and three are earthed. A fourth identical ball placed very far from this system is connected to ball 1 by a thin conducting wire and disconnected. Now fourth ball is connected to ball 2 and then disconnected from it. Again connected to ball 1 and disconnected. Now it is connected to ball 3 and disconnected and finally connected to ball 1 and disconnected. Find the final charge of all the balls.

#Physics #Electricity and magnetism

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4 Answers

1

keshar ·2009-01-18 11:27:37

please go through the question, do not ignore for it is a bit lengthy.

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1

Honey Arora ·2009-01-18 22:14:39

for balls 1-3 +ve
for 4th ball -ve

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Lokesh Verma ·2009-01-18 22:18:37

but what is the exact value in terms of Q and R?

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keshar ·2009-01-20 03:31:42

Ans: Q₁=(10/19)³Q

Q₂=Q₃= - Q₁/5

Now solve and check your ans.

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