Steady State Analysis

2 Answers

486

Niraj kumar Jha ·2014-02-25 03:24:33

Energy stored on capacitor C₁=18Î¼J,C₂=6Î¼J
Lower plate of C₁ is positively charged.

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Akash Anand Excellent job.
Upvote·0· Reply ·2014-02-25 06:07:56
Sourish Ghosh @niraj can you show how you did this?
Upvote·0· Reply ·2014-02-25 23:07:26
Niraj kumar Jha I did it by superposition principle i.e short circuited the two batteries and found charge due to one and similarly found charges due to other batteries individually ,their sum was net charge.@Sir is there another shorter method?
Upvote·0· Reply ·2014-02-26 02:50:11
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1161

Akash Anand ·2014-02-26 04:42:41

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Anurag Ghosh We will always take the drop along the direction we move?
Upvote·0· Reply ·2014-02-26 17:38:21
Akash Anand Its not necessary, but if you are moving along the direction of current, then it will be drop and vice versa. If there is not current flowing then you may take any of these, but keep that for your complete loop
Upvote·0· Reply ·2014-02-26 22:04:39
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