The threshold frequency for certain metal is 3 × 10^14 Hz. If light of frequency 8.2 × 10^14 Hz is incident
on the metal, predict the cut off voltage for photoelectric emission.
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1 Answers
govind
·2010-02-04 22:00:31
just use the eqn
hν = hν0 + eV
where ν is the frequenct of incident light
ν0 is the threshold frequency
and e = 1.6 *10-19