1
skygirl
·2009-03-31 11:15:49
1.) nLdi/dt + iR = E
=> nLdi/dt = E-iR
=> di/E-iR = dt/nL
=> i = E/R(1-e-t/nL/R)
time constant inc .... so current dec.
this wont last long... only it will last for one time constant.
2.) When the circuit is again in steady state the ncurrent in inductor is= E/R
1
skygirl
·2009-03-31 11:19:29
am sorry not 1 time constant ...
24
eureka123
·2009-03-31 11:39:57
Q3 one more question..........
after insertion of rod which queantities will change
a)potential diff across inductor
b)rate of heat produced in coil