why a wire does not produce an enctirc field

its maybe becos if we consider a crossection of a wire...the electric field comes out to be 0..

Take one cross section of a wire (dS) and isolate it..
In that crossection there were protons and electrons.
The protons were fixed in the crosssection and electrons moved.

now this isolated crossection has Zero net charge
=> Zero Electric field

in a similar way Every crossection will contribute zero electric field.

So net field is Zero

so i was sort of right....i never expected....

@eure how the net charge enclosed by the surface dS is zero at all times.Can u explain a bit i cant get u.

but i think the explanation will be easier if we apply gauss's law to the entire conductor that carries currents.Draw a gaussian surface which encloses the current carrying conductor,Gauss law states that field outside the conductor is due to the q_en but here q_en=0 since the conductor is electrically neutral.

But in actual practice the field is not zero,there will be charge accumulation at the twists and turns of the conductor,due to them there will be field.

i want ne1 to confirm my explanation.

according to me the right answer comes when we are using gausss law or using the property of drift vel ......

see the drift vel concept
consider a length of the wire it is obviusly a condicutor and has free elctronns
the numbeer going out is equal to the number coming in so reultant charge at any instatn of time is 0

but i think the mest method is the gauss law

@ varun my explaianaton is also the same..its just that i didt use that Gauss law word

since net charge is zero in any crossection,so electric field is zero
E.S=q_net/ε