18-02-2009 maths: probability

hey mathematician look for it,

case 1: when c is not needed

fixing b a pt.(later we'll see for b also)a can be placed at 90/360 ways ,also in both sides therefore its 2 x 90/360

further when c is not needed in between a and b therefore it placing probability take value 2 x 270/360 (2 x as for both case of a being on either sides).

Also b can be placed in any angle threreforp() = 1/360

therefore the net prob being

(2 x 90/360) x (2 x 270/360) x (1/360)

similarly case2:when c is needed for communicating

what do u say mathematician , correct me if i am wrong , bash if the solution is absurd ,but respond positively.

hey dude, the answer is (Î +2)/4Î now u check where u have gone wrong!!!!!!!!!!!!!!!!!!!

ok fine fine iadmit some thing might have gone wrong so plz expln how to proceed??