a+b

If a is a natural number and b a digit such that (3a+2007)²=4b85924' then a+b=

a.31 b. 35 c.37 d. 41

5 Answers

1357

Manish Shankar ·2009-01-26 23:49:16

left side is multiple of '9'

so sum of the digits on RHS should be multiple of 9

b+32=9n
this might help

my answer is 41.

can some one explain this

taking forward manish's arguement..

b+32=9n

b is less than 10

so 36 is the only possibleiyt ie b=4 and n=4

√4485924=2118

hence 3a+2007=2118

3a=111

a=37

and thus, a+b=41

thanks bhaiyya

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω