binomial

Using binomial theorem, the value of (0.999)3 correct to 3 decimal places is
(A) 0.999 (B) 0.998 (C) 0.997 (D) 0.995

2 Answers

abv is ( 1 - 0.001 )³

now use binomial expansion and try to solve

x=1
âˆ‚x=-0.001
if y=x³, âˆ‚yâ‰ˆ3x²âˆ‚x = 3*1*(-.001)
so y(.999)=y(1)+âˆ‚y
thats what they want u to do in this problem.

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