21how about that ?
actually quadrilaterals inscribed in a circle which has only one diagonal passing through the center of the circle are all of such form...
In the above figure we see four line segments intersecting at
A,B,C and D respectively. LA = 900, LC = 900.
Surely, LB = LD = 900. So how can we prove it theoretically...!
Practically its true and obvious but can that be proved theoretically..?
(i'm confused)
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4 Answers
21u cant prove it because not always B =D=90° ( it must be given AD and BC are parallel)
draw figure in some other fashions u will get cases where A=C=90 B≠D≠90
36@shubhodip -> Hi! dear.... there can be no such case that A=C=90 B≠D≠90......????
2136gr8.... I was totally cofused and couldn't figure it out......!!!!!!!!!!!!!!.....
THANKS....