Controversy???

A Satya's Corner tpe of question!!!

What is the value of log\left[(x+1)^{2} \right] at x=-2009???

Aragorn and Anirudh say:

It is 2log\left[-2009+1 \right] and thus undefined as the thing inside is negative...

Earendil and Iluvatar say:

It is log\left[(-2009+1 \right)^{2}] and the term inside is well and truly positive and so the answer too must be defined

Which group is correct??

4 Answers

106
Asish Mahapatra ·

it is defined.. bcz .. logax = x*log lal provided ax is positive

1
ith_power ·

I think second one. because we have to take MODULUS in this type of cases.

106
Asish Mahapatra ·

nice ani only says both I and II [3]

11
Anirudh Narayanan ·

hehe...[3]

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