1ya kuch kuch yaad aara ahi
i guess it wrks only wen m is betwn a/b and -a/b
(sorry if itz wrng virtual think kiya :P)
Eqtn of normal to hyperbola : y = mx \pm [m(a^{2} + b^{2}) / \sqrt{a^{2}-b^{2}m^{2}}]
then if m takes higher values thn a2 - b2m2 bcums -ve [5]
hayla yeh kya hua, kaise hua, hyun hua???
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4 Answers
341go back to how you obtained the equation to the normal. See if they spoke of some discriminant.
Physically, see if there are lines above a certain slope that cannot intersect a hyperbola?
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21yah true SIR,
aisa hi kuch mein soch raha tha jab i typd da questn....
that non-intersecting portion is very true!!!
thnq