39so glad that its done :P
\left|y \right|=\left(x-\left[x \right] \right)^{2}
iseh banao, accha dikhta hain i mean draw its graph
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23 Answers
62manipal your graph is a bit wrong..
I know you have made a very slight error..
check the mistake :)
1haha [1] i got a pink for that lazy post....
i do tend to get in a mood like this in the afternoon...
11like..............
i have mentioned earlier that it would be continous and non differentiable
what more things[7][7][7]
1@manipal [11]no one more thing ......
read my previous post if it makes any sense those U's dont touch each other
11made the worst possible mistake
{x} 1 se zyada nahin hota[2][2][2]
1the graph will be like many U's and their reflection in the mirror named as x axis
not to mention the "nails" that fix that mirror on the ground
evenly distributed at intervals of 1 unit [1]
1shift all those portions down to touch the x axis manipal....
i thought this was done as soon as tapan replied.......
21|y| = {x}2
let us consider 0<x<1
to ye ho jaega y = x2 matlab parabola........
ab isko repeat karte jao ..... nad ya at x = int, y = 0
it is symmetric abt the x-axis.......
11THE GRAPH WILL BE CONTINUOUS AND NON DIFFERENTIABLE AT INTEGRAL POINTS
11{x}=x when 0<x<1 {x}=1-x when -1<x<0
{x}=x-1when1<x<2 {x}=2-x when -2<x<-1....................
{x}=x-2when 2x<3........................
and the ques is \left|y \right|=\left\{{x} \right\}^{2}
so sending the graph in next post
1357no virang.. tis is no the correct analysis...
Will it be linear?
11mod Y= {x}2
Since its squared the answer has to positive
Therefore
Y = {x}2
{x}
Therefore Y = 0 to 1(not to include 1)
Nishant bhaiyya am i rite or not?
