9byah uve stated definition of lcm wrongly !!!!
LCM of two fractions -- a1/b1 & a2/b2 is = LCM(a1,a2) / HCF(b1.b2) . Prove
-
UP 0 DOWN 0 1 11
11 Answers
62LCM of two fractions -- a1/b1 & a2/b2 is = LCM(a1,a2) / HCF(b1.b2) . Prove
This is a very good question
I likke the fact thta you have questioned this result.
Lets see why
LCM is a number which when multiplied by an integer gives both the numbers.
THe proof I think holeds only if a1, b1 are coprime to each other and a2, b2 are coprime to each other.
With this much in mind.. let us say that p/q is the lcm
now n.p/q = a1/b1
and m.p/a= a2/b2
Will this much info satisfy the whole thing?
11what does "coprime" mean./.. I didnt get the last part specially 2nd last line...can sum1 pls explain.
62ronald.
coprime means prime to each other.. means no common factors
like 10 and 27
both are coprime to each other.
9no no that
LCM is a number which when multiplied by an integer gives both the numbers.
it shud be
LCM is least number which is a multiple of both the given nos
1ya..celestine is right...it shud be the least multiple of both the nos..
nishant bhaiya, plz reply..
i ws doing the same thing the other way..
if p/q is the LCM, then
m\frac{a_{1}}{b_{1}} = n\frac{a_{2}}{b_{2}}=\frac{p}{q}
where m and n are least possible natural nos.
for p/q to be smallest, p should be as small as possible and q should be as large as possible..
but what next??? cudnt think of nething else...