11
Mani Pal Singh
·2009-03-15 03:50:17
TRIGONOMETRY +2 KE BOARDS MEIN NAHIN HAI[3]
11
Subash
·2009-03-13 08:43:45
hey KR 2 is wrong i think limits are not -a to +a sort
1
Akand
·2009-03-13 08:10:47
u gotta be kiddin sky..........thts wat they teach u at d startin of d year....d principle intervals of inverse functions......
wel i guess u do complex and difficult questions only hehehe...[3][3]
k...take d interval for tan inverse and ull get in a second....its a ONE mark question........
try 2nd its nice...may take a while
1
Anuj
·2009-03-13 08:16:31
tryin' the 3rd.........
what to do in 1st and 2nd
1
Akand
·2009-03-13 08:18:20
wat do u mean wat to do??????
INTEGRATE in 2nd.............................and find d final value in 1st......
11
Mani Pal Singh
·2009-03-13 08:19:34
1)principal value of tanx varies from-∩/2 to ∩/2
so ∩/6+∩/6=∩/3
1
Anuj
·2009-03-13 08:21:10
3. Rs 1350
a works for 5 days, B works for 3 days
11
Mani Pal Singh
·2009-03-13 08:21:57
2)HINT its an ODD function[1]
1
Anuj
·2009-03-13 08:22:04
i mean how to integrate???
and how to proceed in 1st????
1
Akand
·2009-03-13 08:24:13
hey mue................check tht 3rd again.....u r gettin an unbounded region rite?????? so did u try for 150x+200y<1350??? thts d tricky part..............u havent finishd d question yet..
1
KR
·2009-03-13 08:24:19
1)=tan^{-1}\left(tan\left(\frac{7\pi }{6} \right) \right)+cot^{-1}\left(cot\left(\frac{7\pi }{6} \right) \right) \Rightarrow tan^{-1}\left(tan\left(\pi +\frac{\pi }{6} \right) \right)+cot^{-1}\left(cot\left(\pi +\frac{\pi }{6} \right) \right)\Rightarrow tan^{-1}(tan(\frac{\pi }{6}))+cot^{-1}(cot(\frac{\pi }{6}))\Rightarrow \frac{\pi }{3}6)
1
Anuj
·2009-03-13 08:32:31
i dont know what to do of graph...[2][2][2]
1
KR
·2009-03-13 08:35:52
let f(x)=o∫∩/2(x+sinx)dx/(1+cosx)...
i think we can get after splitting it........
and putting cosx =t;{thinking.........}
1
KR
·2009-03-13 08:39:43
[17] [17] sorry MS , i was RENDERING EQUATION using that LATEX , it really took a lot of time..[17][17]
1
skygirl
·2009-03-13 08:04:00
yeh pehla wala mereko koi batado kaise karte hai ....
1
Akand
·2009-03-13 08:44:45
yup........................i told its tricky
11
Subash
·2009-03-13 08:45:21
seprating it into two integrals would be the trick i think
11
Mani Pal Singh
·2009-03-13 08:46:13
good catch subash
at least arent fooled by my ststement
it was just a fact and not a way to approach a problem
1
Akand
·2009-03-13 08:48:20
wel subash there is an easier trick..........think cbse ques??
1
prateek punj
·2009-03-13 08:48:39
hey akand r these just the ques by u or hav any resource that u r writting them to be coming in brds...
1
Akand
·2009-03-13 08:54:38
try tht............i tried to.........u wont get it.......
11
Subash
·2009-03-13 08:55:15
ya this is a really tricky one im not getting that way
1
Akand
·2009-03-13 08:57:40
wel....try these ill giv more...............wel prateek this wasa pre board 3 q paper.......but we dint hav any preboard 3 so sir just gave it to us..
11
Mani Pal Singh
·2009-03-13 08:58:10
i have a method but a lenghty one so find a new 1
1+cosx=2cos2x/2
=0∩/2∫xsec2x/2+tanx/2
i hope iske aage koi bhi kar sakta hai!!!!!!!!!!!!
(use product rule for 1)
1
KR
·2009-03-13 08:58:57
by splitting we can get the right part but left part thinking.......
1
Akand
·2009-03-13 09:01:04
manipal............u wer on d edge gettin a lot easier method......but missed