USE area = 1/2 ab sin c
a=b=2011
maximum area is when sin c is max
so c is 90 degree
so the third side is 2011 √2
If the length of the equal sides of an isoceles triangle is 2011, find the length of the third side such that its area is maximum.
USE area = 1/2 ab sin c
a=b=2011
maximum area is when sin c is max
so c is 90 degree
so the third side is 2011 √2