this was aksed by arka long time back
http://www.targetiit.com/iit-jee-forum/posts/error-analysis-12555.html
had a problem in this all through class 11 so i memorized the result. This was the only result that i memorized in physics in 11 and LOL it proved fruitful!! But i hate the concept of memorizing so i hpe my doubt will be answered in this GENIUS forum...
the problem goes like this:
If the error in the measurement of the momentum of a particle be +100%. Then, the error in the measurement of kinetic energy is:
(a)400%
(b)300%
(c)100%
(d)200%
but before delving into this question let us solve this question...
%age error in the measurement of mass and speed are 2% and 3% respectively. The error in the estimate of kinetic energy will be??
well to solve this problem after using much mathmatical concepts we conclude that
if E=1/2mv2,
then, \frac{\Delta E}{E}=\frac{\Delta m}{m}+2\frac{\Delta v}{v}
or, %age error in E=2%+2X3%=8%........which is the correct answer...
now delving back into the original quest...
we know after applying much physics, we get,
p=√2mE
so, E=p2/4m2
or, \frac{\Delta E}{E}=2\frac{\Delta p}{p}
giving %age change in E=200%
but in all books i found answer given is 300%
even in our exams a question came asking for when the change in K.E. is 100% what is the change in linear momentum, I instead of applying the above technique, straightaway did 100/3% and when papers came out LOL the teacher had given 0.5 out of 1 with the comment "half marks for correct answer without any work out..i must mention others had acheved a 0".[3][3][3] So now that my 11 is over, i want the explanation for this so that i do not get any more HALF MARKS in life for these types of questions!![3][3][3]
subho .......ans is indeed 300%
let me explain dis from a very simple perspective:
to make things simple let mass be =1 kg
let the velo =v.....so ..p(lin. momentum)=v
but since da eror is 100%.....velo shud be "2v".....
dat is p=2v.....
now initial KE=0.5*v2..........and final KE=4v2..
thus..diff in KE=32v2
so..the error in the measurement of kinetic energy is:(3/2)/(1/2)*100=300%
i hope this has made things clear
As far as I remember ..this formula is only valid when the change is very small..so i dont think that this formula can be applied for this question...
HELLO Subho dear !!!
I got it 300% and I was given 1 on 1. Now where did i go wrong ??
this was aksed by arka long time back
http://www.targetiit.com/iit-jee-forum/posts/error-analysis-12555.html