Dimension

Dimension of 1/2 ε0E2 (ε0 is the permittivity of free space, E is electric filed) is?

12 Answers

13
Двҥїяuρ now in medical c ·

[ML-1T-2]

[E]=MLT-3A-1
[ε0] =M-1L-3A2 T4

11
Anirudh Narayanan ·

It is the energy density of capacitor i think

1
ANKIT MAHATO ·

M L-1 T-2
energy density in a capacitor
1/2 (εA/d)(V)2 = 1/2 (εA/d)(Ed)2 = 1/2 εE2 * volume = energy ...
1/2 εE2 = energy/volume = [M L-1 T-2]

11
Mani Pal Singh ·

E=MLT-3A-1 (F=qE)
ε0 =M-1L-3A2 T4 (F=q1q2/4piε0r2)

SO IT BECOMES

ML-1T-2

13
Двҥїяuρ now in medical c ·

@mani

[ε0]=[M-1L-3A2 T4]

11
Mani Pal Singh ·

SORRY BRO COPY MEIN GANDI WRITING SE LIKHA THA
SORRY
(EDITED)

1
rahul nair ·

i think its [M^{1}L^{-1}T^{-4}A^{2}]
@abhi, electric field intensity is [M^{1}L^{1}T^{-3}A^{-1}]....are electri field and electric field intensity the same.................electric intensity is the strength of electric field.......i m not sure...but someone pls clear my doubt...........

1
ANKIT MAHATO ·

mani ne bhi toh yahi likha hai E ka dimension !!

1
rahul nair ·

Nishant bhaiyya, wat's the answer????????????

1
Optimus Prime ·

nishant bhaiya is not replying since morning

1
greatvishal swami ·

its energy density naa

so dimen =ML2T-2/L3

=ML-1T-2

1
greatvishal swami ·

but bhiya iit main to is Q ka koi opt nahi tha [7][7]

matlab sahi ans options main nahi tha

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