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since the surface is frictionless the COM always moves along the line x=0.
if the coordinates of the point R be (x,y) then
(L-R)cosθ = x and Rsinθ = y
eliminating θ, we get locus of the point as
x2 / (L-R)2 + y2 / R2 = 1 which is an ellipse
a uniform rod of length 2L and mass M is kept vertically (along the Y axis) on a frictionless surface. its end point is at origin.. suddenly its end point starts sliding on the plane along the positive X axis..find the locus of the point which is at a distance R from the end point..
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7 Answers
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21alternative: (l/a) =(r-l)/x
(x+ a )^2 + y^2 = R^2
eliminating a,we get the equation///
1@euclid : hey there is a mistake in the fig.... the length which u 've marked as (L-R)cosθ is wrong... it will be the length measured from the origin.. nd nt from the base of the rod....
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