thnx swaraj.
Ans. 1
i seem to have completely forgotten this .
some help plz.
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2 Answers
Swaraj Dalmia
·2012-02-15 04:17:11
Take initial extension to be x(kx=100) and extension after pulling it be y.
Now energy of oscillation = extra energy stored in it after pulling.
=1/2*k*(y2-x2)
=1/2*k(y-x)(y+x)
Now using pythagoras y-x=.0002
Now approximating (y+x) to 2x (will not work if k is too large as the difference will be magnified)
=1/2*k*.0002*2x
=.02=1/50