11D = M/V
D= M/l*2∩R2
Therefore % error is
E = {0.06/6 + 0.005/0.5+ 0.003/0.3) *100
E = [0.01 + 0.01*2 + 0.01) *100
E = 4%
Is it rite sir?
A wire of length l=6±.06 cm and radius =0.5±0.005 cm and mass m=0.3±0.003 gm.
maximum percentage error in density is ?
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3 Answers
1density = mass / π r2 l
% error in density = % error in mass +2* % error in radius + % error in length
= 1 % + 2* 1% + 1% = 4 %
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