Error Analysis

If the error in measuring momentum is +100%,then the error in measurement of kinetic energy is :
a>400% b>300% c>100% d>200%

10 Answers

24
eureka123 ·

c)

24
eureka123 ·

tell me if its right or wrong..

1
Arka Halder ·

answer given is b

1
Arka Halder ·

do we have to assume that the error in measurement of mass is 0?in that way i'm getting 200%.

24
eureka123 ·

looks liek i am confused with ur options

are they >100 and so on ???

or 100,200 ???

1
Arka Halder ·

no not greater than...option a is 400%,b is 300%,c is 100% and d is 200%.

24
eureka123 ·

DOnt know I am right or not...but this may inspire others to solve it

p=m.v
Case1: Let error be in measuring mass..
=> Δp/p *100=Δm/m *100=100

K=p22m
=> ΔKKx100=2Δppx100+Δmmx100

=> ΔKKx100==2(100)+100=300

=>300%

Case2: If error is in velocity
=> Δp/p *100=Δv/v *100=100

K=pv2
=> ΔKKx100=Δppx100+Δvvx100

=> ΔKKx100==100+100=200

=>200%

1
Arka Halder ·

Yes.I totally agree.Actually i had taken error in velocity and proceeded.
Unless mentioned in the sum its difficult to understand.

24
eureka123 ·

ya..it should have been mentioned....but now i hope its solved..

1
Arka Halder ·

yeah.thanks.

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