FTJEE AITS Phy..

Q.1

answer given is (c) but i got (d) [2][7]

13 Answers

33
Abhishek Priyam ·

this was one of the four question jo nahi bana paper 2 me...

[2]

62
Lokesh Verma ·

yaar poora diagram dikha do..

the method should be to take equate the force

Jitna mere ko samajh aaya..
kq2/h2=2.T.2pi.R.(h/r) (h/r is approximate for sin theta) (The 2 comes because there are 2 surfaces. and there will be tension due to each surface..)
(Solution by eureka..)

so I think this should solve..

33
Abhishek Priyam ·

diag me bas ek point charge hai last me... +q ka...

62
Lokesh Verma ·

so isnt h3 = q2/(8pi2Tε)

which is the 4th option.. ?

Even I am getting D it seems :(

33
Abhishek Priyam ·

h/R is approximate of cos theta naa...

and isse to D hi aega.. jo mera aya...

they ahve taken Kq2/h2=2 T2Ï€R(h/R)

ek extra 2 kaha se aya..

62
Lokesh Verma ·

wahi theta.. I took the other angle to be theta..

and din see ur post... so changed the above option..

33
Abhishek Priyam ·

capacitor one..[7]

ye silly wala pata nahi kyun nahi bana..

1
skygirl ·

haan .. mujhe kaise B aya tha... ans A hai :( :(

24
eureka123 ·

extra 2 becoz its ring........[1] so double layer....[1]

33
Abhishek Priyam ·

ooohh

1
Grandmaster ·

what do u say

24
eureka123 ·

where is net charge dear?????[7]

1
Vivek ·

for the capacitor one,the charges will redistribute to 3Q/2 each,then since the charges are now equal and the caps are in series,an effective capacitor of C/2 and charge 3q/2 gives the answer (A)

1/2Li2= (3q/2)2/(2*(C/2))

i = 3q/√2LC

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