1well,
this is the reaction: CaCO3 + 2 HCl → CaCl2 + CO2 + H2O
one mole of CaCO3 gives 1 mole of CO2. so 2.5/100 moles of caco3 gives 2.5/100 mol of co2 ≡ 2.5/100 * 22.4 L
The volume of CO2 gas formed when 2.5g calcium carbonate are dissolved in excess hydrochloric acid at 0degree celsius and 1atm pressure is ?
{1 MOLE OF ANY GAS AT 0 DEGREE CELSIUS AND 1 ATM PRESSURE OCCUPIES 22.414L VOLUME}
A)1.12L
B)56.0L
C)0.28L
D)0.56L
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3 Answers
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