11
SANDIPAN CHAKRABORTY
·2010-05-06 07:44:14
EDITED
1)The answer is 1:15 pm.
Let the total distance b/w thestations be D
In the 15 mins till B starts A travells D/10
so eff dist b/w A and B now is (9/10)D
Let after time t the trains meet
then for train A
distnc travelled L in time t
L = D2.5 x t ..........(1)
for train B to meet A , B must have travelled (9/10)D - L in time t
(9/10)D - L = D2 x t .........(2)
PLugging in the value of L in (2) from (1) we get t = 1 hr
So they meet after 1 hr 15 mins wrt to train A (the 15 mins A travelled till B started)
so they meet at 12:00 + 1 hr 15 mins
====>1:15 pm
1
1.618
·2010-05-06 07:46:47
Shud b under 9-10th forum...:)
11
SANDIPAN CHAKRABORTY
·2010-05-06 10:18:14
Q3) ans is spirit:water = 10:1
The cost of 1L spirit is Rs 60
Let xL water be added per litre of spirit
Now SP of 1 L mixture = Rs 75
so (x+1) L costs = Rs (x+1)75
% profit = 75(x+1) - 6060 x 100 = 37.5
solving we get x = 110
so 1L spirit : 110 L water
or 10 L spirit : 1L water
so ratio spirit:water = 10 : 1
11
SANDIPAN CHAKRABORTY
·2010-05-06 10:37:17
Q4)
10 % adultration means 90 parts petrol has 10 parts impurity
Let amount of petrol added be x
so 90 + x100 + x = 98100
==> x = 400 parts...
now 400 parts of petrol to be added per 100 parts of adultrated
petrol...
so 400% of adultrated petrol to be replaced with pure petrol