Vectors

There is a simple method of doing this.
Let A be the smaller vector of magnitude "x".
Then B would be the larger Vector with magnitude (16-x).
Resultant Vector|(A+B)|=8
The triangle would look like-
A right-angled triangle with vector A as the base, resultant vector (A+B) as the perpendicular and Vector B as the hypotenuse.
Using Pythagoras's Theorem-

64+x²=(16-x)²
64+x²=256+x²-32x
32x=256-64
32x=192
x=6
Hence the answer will be-
|A|=6
|B|=10
Let me know if you think I have gone worng :)

thanks