let surface velocity of earth be v kmph
and A be to the East of B
therefore, time taken from A-B = 1000/(500+v)
similarly, time for B-A = 1000/(500-v)
v can easily be found by finding w (ang. vel.) and r=6400km
There are to points A and B on the earth surface at equator separated by 1000km.An aeroplane flying at a constant speed of 500km/h goes from A to B directly and then B to A directly.
How much will it take in each case.
u talking about the speed wrt to the earth's surface or also want to account for the rotation of earth?
let surface velocity of earth be v kmph
and A be to the East of B
therefore, time taken from A-B = 1000/(500+v)
similarly, time for B-A = 1000/(500-v)
v can easily be found by finding w (ang. vel.) and r=6400km
linear speed of point on earth surface at equator is 1660km/h that means point B is moving faster than plane
There are to points A and B on the earth surface at equator separated by 1000km.An aeroplane flying at a constant speed of 500km/h goes from A to B directly and then B to A directly.
How much time will it take in each case.