4x-2[x]=y
[x]=0 for x belongs [0,1)
we have to do the same for all the other intervals.
4x-2[x]=y
[x]=0 for x belongs [0,1)
we have to do the same for all the other intervals.
its basically this
for x = [k,k+1)
the equation is y=4x/4k here u shud take x as [0,1)
@vector: there will be concavities and convexities please show them.
the values u have shown are fyn.
Also show the portion of negative x.