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With the time left now fir jee 2010 ....i must do only ncert na for (11 & 12 ) ...for inorganic/?? to get atleast average score in inorganic? ...
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Xenon is in sp3 hybridisation in 1. XeO4 2. XeF4 3. XeO3 4. XeO2 a) 2,4 b) 1,2 c) 1,2,3 d) 2 ...
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Q1 K2Cr2O7 +H2SO4(hot)→ Q2 K2Cr2O7 +H2SO4(cold)→ Q3 K2Cr2O7 +H2SO4(room temperature)→ Q4 Hydrated FeCl3 + Stream of air(high tempearture)→ Q5 Ferric oxide +HCl → Q6 Na2CrO4 +C +heat → Q7Mixture of KCr2O7 and conc ...
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1) An oxy-acid of phosphorous is prepared by hydrolysis and oxidation of red P by NaOCl or yellow P by H2 O and air . What is the basicity of the oxyacid ? Ans 4 ...
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1.what methods can be used to distinguish between cis and trans isomers of an complex???? ...
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1...among the following C-O bond order is lowest in : (a)[Mn(co)6]+ (b)[Fe(co)5] (c) [Cr(co)6] (d)[V(co)6] 2..why Cr3+ never forms tetrahedral complexes even if V3+, Fe3+ form ???????? 3.. hich can xists as disastereomers ??? ...
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Which of the following is coloured due to polarisation? 1. Ag3PO4 2. Cu2Cl2 3. K4[Fe(CN)6] 4. CuF2 ...
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The co-ordination number of Cr in [Cr(Ï€6-C6H6)2 ] is x. Then x/2 will be ? ...
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Calculate number of geometrical isomers of complex [Cr(NH3)3Cl3] ? ...
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Atomic radii of fluorine and neon in Angstrom units are respectively given by A. 0.72,1.60 B. 1.60,1.60 C. 0.72,0.72 D. None of these. If we dont know the exact values,should we go for option A although there is an option lik ...
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How many sp3 hybridised atom in (SO3)3 solid? ...
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Which of the following compounds is expected to be coloured ? A. Ag2SO4 B CuF2 C. MgF2 D. CuCl have doubt b/w B n D ...
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DELETED ...
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Argon is used in arc welding because of its A. low reactivity with metal B. ability to lower the melting point of the metal C. flammability D. high calorific value ...
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The material used in the solar cell contains A. Cs B. Si C. Sn D. Ti ...
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1. S1 : Al(OH)3 is amphoteric in nature. S2 : Al-O and O-H bonds can be broken with equal ease in Al(OH)3. ...
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When PbO2 reacts with conc HNO3,the gas evolved is (A). NO2 (B). O2 (C) N2 (D). N2O ...
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1. Account for the followiong a. CO2 is gas, but SiO2 is a solid b. (CCl4 is resistant to hydrolysis, but SiCl4 is hydrolysed 2. What is radius ratio ? What is its significance. ...
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d only cation present in a slight acidic sol. are Fe+3, Zn+2 and Cu+2 . d reagent dat when added in excess to this sol. would identify and separate Fe+3 in one step. a. 2 M HCl b. 6 M NH3 c. 6 M NaOH d. H2S gas ...
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1. Which one among the following pairs of ions cannot be seperated by H2S in dil HCl ? A. Bi3+,Sn4+ B. Al3+,Hg2+ C. Zn2+,Cu2+ D. Ni2+,Cu2+ (1986) 2. Hydrogen gas will not reduce (A). heated Cupric Oxide (B). heated ferric oxi ...
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The compounds used as refrigerant are -- (A). NH3 (C). CF4 (B). CCl4 (D). CF2Cl2 (E). CH2F2 A is one correct option ...
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wht is the hybridisation of boron in borax? ...
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Explain tetrahedral Ni (II) complexes are Paramagnetic but squaire planar Ni (II) complexes are diamagnetic. ...
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1/ Which of the following metals have both valence and penultimate shell partially filled A. Cr B.Mo C.Cu D.Zn 2/ Which wil give ammonia with water A. Mg3N2 B.AIN C.CaCN2 D.Ca(CN)2 ...
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ncert question hai.....pahli baar kitab kholi hai....[3] Cobalt(II) is stable in awueous soln but in presence of complexing reagents,it is completely oxidised.why?? thread closed ...
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Single Option Correct. 1) Electron Affinity is +ve when- A) O- is formed from O. B) O 2- is formed from O-. C) O+ is formed from O. D) Electron Affinity is always negative. 2)Of the 4 ∂H values needed to calculate the latti ...
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Azide ion exhibts an N-N bond order of 2 and may be represented by resonance structures,I,II,III given below *Image* which of the above structures will contribute more to the resonance hybrid ...
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Why does only Cu2+ form precipitate by passing H2S gas through an acidified solution but not Zn2+? ...
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1.CH3CH2Br (catalyst -aq. NaOH) ----> [A] +(catalyst- K2Cr2O7 H2SO4) ---------> [B] 2. (CH3COO)2 Ca (heat)------>[A]+ (catalyst - Zn/ HCl) ----->[B] ...
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silver bromide is solubel in which of th following? hypo NaCN ammonia all of these? ...